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10k^2+47k-15=0
a = 10; b = 47; c = -15;
Δ = b2-4ac
Δ = 472-4·10·(-15)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-53}{2*10}=\frac{-100}{20} =-5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+53}{2*10}=\frac{6}{20} =3/10 $
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